129x/x^2=3

Solution for 129x/x^2=3 equation:

129x/x^2=3

We move all terms to the left:

129x/x^2-(3)=0


Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


129x-3*x^2=0

We add all the numbers together, and all the variables

-3x^2+129x=0

a = -3; b = 129; c = 0;
Δ = b2-4ac
Δ = 1292-4·(-3)·0
Δ = 16641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16641}=129$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(129)-129}{2*-3}=\frac{-258}{-6}
=+43
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(129)+129}{2*-3}=\frac{0}{-6}
=0
$